PPIO 上线 PaddleOCR-VL-1.5 :小参数高性能 | 一键部署

分享
PPIO 上线 PaddleOCR-VL-1.5 :小参数高性能 | 一键部署

PPIO 算力市场首发上线了 PaddleOCR-VL-1.5 模型模板。

作为 PaddleOCR-VL 系列的全新迭代版本,PaddleOCR-VL-1.5 在保持 0.9B 轻量级参数的同时,性能实现了显著提升 。在权威评测集 OmniDocBench v1.5 上,该模型取得了 94.5% 的精度,优于当前主流的通用大模型及文档解析专用模型。

该模型创新性地支持了文档元素的异形框定位,在扫描、倾斜、弯折、屏幕拍摄及复杂光照等真实落地场景中表现出色,能够精准返回多边形检测框。此外,模型还新增了印章识别与文本行定位功能,并优化了生僻字、古籍及多语种表格的解析效果。

现在,您可以通过 PPIO 算力市场的 PaddleOCR-VL-1.5 模板,将该模型一键部署在 GPU 云服务器上。只需简单几步,即可快速体验模型高效的文档解析能力。

一键部署地址:https://ppio.com/gpu-instance/console/explore

#01 GPU 实例+模板,一键部署 PaddleOCR-VL-1.5

step 1: 子模版市场选择对应模板,并使用此模板。

step 2: 按照所需配置点击部署。

step 3: 检查磁盘大小等信息,确认无误后点击下一步。

step 4: 稍等一会,实例创建需要一些时间。

step 5: 在实例管理里可以查看到所创建的实例。

#02 使用示例

第一步

测试用例如下,后续将被命名为 test.py。

import base64
import requests
import pathlib

API_URL = "http://localhost:8080/layout-parsing"  # Service URL

image_path = "./demo.jpg"

# Encode local image to Base64
with open(image_path, "rb") as file:
    image_bytes = file.read()
    image_data = base64.b64encode(image_bytes).decode("ascii")

payload = {
    "file": image_data,  # Base64 encoded file content or file URL
    "fileType": 1,  # File type, 1 means image file
}

# Call the API
response = requests.post(API_URL, json=payload)

# Process the API response data
assert response.status_code == 200
result = response.json()["result"]
for i, res in enumerate(result["layoutParsingResults"]):
    print(res["prunedResult"])
    md_dir = pathlib.Path(f"markdown_{i}")
    md_dir.mkdir(exist_ok=True)
    (md_dir / "doc.md").write_text(res["markdown"]["text"])
    for img_path, img in res["markdown"]["images"].items():
        img_path = md_dir / img_path
        img_path.parent.mkdir(parents=True, exist_ok=True)
        img_path.write_bytes(base64.b64decode(img))
    print(f"Markdown document saved at {md_dir / 'doc.md'}")
    for img_name, img in res["outputImages"].items():
        img_path = f"{img_name}_{i}.jpg"
        pathlib.Path(img_path).parent.mkdir(exist_ok=True)
        with open(img_path, "wb") as f:
            f.write(base64.b64decode(img))
        print(f"Output image saved at {img_path}")

第二步

准备OCR所需的图片 这里使用的是官方案例

https://github.com/PaddlePaddle/PaddleOCR/blob/main/tests/test_files/book.jpg

curl https://raw.githubusercontent.com/PaddlePaddle/PaddleOCR/main/tests/test_files/book.jpg -o demo.jpg 
复制端口映射地址并在 test.py 文件中替换 API URL

第三步

运行 python test.py 检查输出结果

$ python test.py 
{'page_count': None, 'width': 1100, 'height': 708, 'model_settings': {'use_doc_preprocessor': False, 'use_layout_detection': True, 'use_chart_recognition': False, 'use_seal_recognition': False, 'use_ocr_for_image_block': False, 'format_block_content': False, 'merge_layout_blocks': True, 'markdown_ignore_labels': ['number', 'footnote', 'header', 'header_image', 'footer', 'footer_image', 'aside_text'], 'return_layout_polygon_points': True}, 'parsing_res_list': [{'block_label': 'text', 'block_content': "chances of the lottery jachts are also use combination formulas to work out the chances of the other prizes, but it all starts to get a bit fiddly so we'll move on to something else. (How to work out the other lottery chances is just one of the amazing features you'll find at: www.murderousmaths.co.uk)", 'block_bbox': [180, 0, 512, 109], 'block_id': 0, 'block_order': 1, 'group_id': 0, 'block_polygon_points': [[180.0, 0.0], [512.0, 0.0], [512.0, 109.0], [180.0, 109.0]]}, {'block_label': 'paragraph_title', 'block_content': 'The disappearing sum', 'block_bbox': [180, 113, 310, 137], 'block_id': 1, 'block_order': 2, 'group_id': 1, 'block_polygon_points': [[179.04934692382812, 119.45269012451172], [308.8138122558594, 110.3464126586914], [310.1516418457031, 129.41043090820312], [180.38717651367188, 138.51669311523438]]}, {'block_label': 'text', 'block_content': "It's Friday evening. The lovely Veronica Gumfloss has been out with the football team who have all escorted her safely back to her doorstep. It's that tender moment when each hopeful player closes his eyes and leans forward with quivering lips. Unfortunately Veronica's parents heard them clumping down the road and Veronica knows she only has time to kiss four out of the eleven of them if she's going to do it properly.", 'block_bbox': [175, 126, 505, 289], 'block_id': 2, 'block_order': 3, 'group_id': 2, 'block_polygon_points': [[175, 137], [175, 281], [499, 285], [504, 134], [455, 126], [302, 126]]}, {'block_label': 'image', 'block_content': '', 'block_bbox': [179, 282, 491, 471], 'block_id': 3, 'block_order': None, 'group_id': 3, 'block_polygon_points': [[179.0, 282.0], [491.0, 282.0], [491.0, 471.0], [179.0, 471.0]]}, {'block_label': 'vision_footnote', 'block_content': "How many choices has she got? It's  $ ^{11}C_{4} $ which is  $ ^{111}4l \\times 7 $ but for goodness sake DON'T reach for the calculator! The most brilliant thing about perms and", 'block_bbox': [164, 455, 493, 531], 'block_id': 4, 'block_order': None, 'group_id': 4, 'block_polygon_points': [[164, 459], [164, 505], [345, 527], [492, 527], [492, 474], [377, 470], [323, 466], [246, 459], [207, 455], [170, 455]]}, {'block_label': 'number', 'block_content': '94', 'block_bbox': [301, 546, 326, 563], 'block_id': 5, 'block_order': None, 'group_id': 5, 'block_polygon_points': [[301.0, 546.0], [325.0, 546.0], [325.0, 562.0], [301.0, 562.0]]}, {'block_label': 'text', 'block_content': "means that EVERYTHING ON THE BOTTOM ALWAYS CANCELS OUT! It's probably the best fun you'll ever have with a pencil so here we go...", 'block_bbox': [552, 0, 892, 85], 'block_id': 6, 'block_order': 4, 'group_id': 6, 'block_polygon_points': [[552.6058349609375, -9.254895210266113], [895.4388427734375, 13.18508529663086], [890.72705078125, 85.17122650146484], [547.89404296875, 62.73124313354492]]}, {'block_label': 'display_formula', 'block_content': ' $$ \\frac{11!}{4!\\times7!}=\\quad\\frac{11\\times10\\times9\\times8\\times7\\times6\\times5\\times4\\times3\\times2\\times1}{4\\times3\\times2\\times1\\times7\\times6\\times5\\times4\\times3\\times2\\times1} $$ ', 'block_bbox': [573, 74, 880, 128], 'block_id': 7, 'block_order': 5, 'group_id': 7, 'block_polygon_points': [[573, 89], [573, 109], [650, 113], [700, 117], [879, 127], [879, 96], [869, 92], [770, 85], [688, 78], [644, 74], [579, 74]]}, {'block_label': 'text', 'block_content': "(Before we continue, grab this book and show somebody this sum. Rub their face on it if you need to and tell them that this is the sort of thing you do for fun without a calculator these days because you're so brilliant.)", 'block_bbox': [550, 123, 889, 219], 'block_id': 8, 'block_order': 6, 'group_id': 8, 'block_polygon_points': [[550, 123], [550, 204], [660, 208], [883, 218], [888, 141], [697, 127], [648, 123]]}, {'block_label': 'text', 'block_content': "Off we go then. For starters we'll get rid of the 7! bit from top and bottom and get:", 'block_bbox': [549, 203, 887, 253], 'block_id': 9, 'block_order': 7, 'group_id': 9, 'block_polygon_points': [[549, 203], [549, 238], [886, 252], [886, 218], [792, 214], [676, 207]]}, {'block_label': 'display_formula', 'block_content': ' $$ \\frac{11\\times10\\times9\\times8}{4\\times3\\times2\\times1} $$ ', 'block_bbox': [677, 255, 769, 292], 'block_id': 10, 'block_order': 8, 'group_id': 10, 'block_polygon_points': [[677.0, 255.0], [769.0, 255.0], [769.0, 292.0], [677.0, 292.0]]}, {'block_label': 'text', 'block_content': "Pow! That's already got rid of more than half the numbers. Next we'll see that the  $ 4 \\times 2 $ on the bottom cancels out the 8 on top (and we don't need that “×1” on the bottom either). We're left with...", 'block_bbox': [547, 300, 886, 376], 'block_id': 11, 'block_order': 9, 'group_id': 11, 'block_polygon_points': [[547.0, 299.99993896484375], [886.40771484375, 307.02911376953125], [885.0, 375.0], [545.59228515625, 367.9708251953125]]}, {'block_label': 'display_formula', 'block_content': ' $$ \\frac{11\\times10\\times9}{3} $$ ', 'block_bbox': [685, 384, 756, 417], 'block_id': 12, 'block_order': 10, 'group_id': 12, 'block_polygon_points': [[685.0, 384.0], [756.0, 384.0], [756.0, 417.0], [685.0, 417.0]]}, {'block_label': 'text', 'block_content': "Then the 3 on the bottom divides into the 9 on top leaving it as a 3 so all we've got now is:", 'block_bbox': [545, 429, 884, 468], 'block_id': 13, 'block_order': 11, 'group_id': 13, 'block_polygon_points': [[545.0, 429.0], [884.0, 429.0], [884.0, 468.0], [545.0, 468.0]]}, {'block_label': 'text', 'block_content': "Veronica's choices = 11 × 10 × 3", 'block_bbox': [618, 477, 817, 496], 'block_id': 14, 'block_order': 12, 'group_id': 14, 'block_polygon_points': [[618.0, 477.0], [816.0, 477.0], [816.0, 495.0], [618.0, 495.0]]}, {'block_label': 'text', 'block_content': 'Look! No bottom.', 'block_bbox': [543, 508, 666, 529], 'block_id': 15, 'block_order': 13, 'group_id': 15, 'block_polygon_points': [[542.9999389648438, 508.0], [664.9999389648438, 508.0], [664.9999389648438, 528.0], [542.9999389648438, 528.0]]}, {'block_label': 'number', 'block_content': '95', 'block_bbox': [705, 555, 729, 571], 'block_id': 16, 'block_order': None, 'group_id': 16, 'block_polygon_points': [[705.0, 555.0], [728.0, 555.0], [728.0, 570.0], [705.0, 570.0]]}, {'block_label': 'image', 'block_content': '', 'block_bbox': [938, 0, 1099, 647], 'block_id': 17, 'block_order': None, 'group_id': 17, 'block_polygon_points': [[938.0, -2.0], [1099.0, -2.0], [1099.0, 647.0], [938.0, 647.0]]}], 'layout_det_res': {'boxes': [{'cls_id': 22, 'label': 'text', 'score': 0.9220595955848694, 'coordinate': [180, 0, 512, 109], 'order': 1, 'polygon_points': [[180.0, 0.0], [512.0, 0.0], [512.0, 109.0], [180.0, 109.0]]}, {'cls_id': 17, 'label': 'paragraph_title', 'score': 0.8456085920333862, 'coordinate': [180, 113, 310, 137], 'order': 2, 'polygon_points': [[179.04934692382812, 119.45269012451172], [308.8138122558594, 110.3464126586914], [310.1516418457031, 129.41043090820312], [180.38717651367188, 138.51669311523438]]}, {'cls_id': 22, 'label': 'text', 'score': 0.9213816523551941, 'coordinate': [175, 126, 505, 289], 'order': 3, 'polygon_points': [[175, 137], [175, 281], [499, 285], [504, 134], [455, 126], [302, 126]]}, {'cls_id': 14, 'label': 'image', 'score': 0.9448813199996948, 'coordinate': [179, 282, 491, 471], 'order': None, 'polygon_points': [[179.0, 282.0], [491.0, 282.0], [491.0, 471.0], [179.0, 471.0]]}, {'cls_id': 24, 'label': 'vision_footnote', 'score': 0.8173566460609436, 'coordinate': [164, 455, 493, 531], 'order': None, 'polygon_points': [[164, 459], [164, 505], [345, 527], [492, 527], [492, 474], [377, 470], [323, 466], [246, 459], [207, 455], [170, 455]]}, {'cls_id': 16, 'label': 'number', 'score': 0.7621420621871948, 'coordinate': [301, 546, 326, 563], 'order': 4, 'polygon_points': [[301.0, 546.0], [325.0, 546.0], [325.0, 562.0], [301.0, 562.0]]}, {'cls_id': 22, 'label': 'text', 'score': 0.913713276386261, 'coordinate': [552, 0, 892, 85], 'order': 5, 'polygon_points': [[552.6058349609375, -9.254895210266113], [895.4388427734375, 13.18508529663086], [890.72705078125, 85.17122650146484], [547.89404296875, 62.73124313354492]]}, {'cls_id': 5, 'label': 'display_formula', 'score': 0.8774852156639099, 'coordinate': [573, 74, 880, 128], 'order': 6, 'polygon_points': [[573, 89], [573, 109], [650, 113], [700, 117], [879, 127], [879, 96], [869, 92], [770, 85], [688, 78], [644, 74], [579, 74]]}, {'cls_id': 22, 'label': 'text', 'score': 0.9250841736793518, 'coordinate': [550, 123, 889, 219], 'order': 7, 'polygon_points': [[550, 123], [550, 204], [660, 208], [883, 218], [888, 141], [697, 127], [648, 123]]}, {'cls_id': 22, 'label': 'text', 'score': 0.8921533823013306, 'coordinate': [549, 203, 887, 253], 'order': 8, 'polygon_points': [[549, 203], [549, 238], [886, 252], [886, 218], [792, 214], [676, 207]]}, {'cls_id': 5, 'label': 'display_formula', 'score': 0.7999240159988403, 'coordinate': [677, 255, 769, 292], 'order': 9, 'polygon_points': [[677.0, 255.0], [769.0, 255.0], [769.0, 292.0], [677.0, 292.0]]}, {'cls_id': 22, 'label': 'text', 'score': 0.9141753315925598, 'coordinate': [547, 300, 886, 376], 'order': 10, 'polygon_points': [[547.0, 299.99993896484375], [886.40771484375, 307.02911376953125], [885.0, 375.0], [545.59228515625, 367.9708251953125]]}, {'cls_id': 5, 'label': 'display_formula', 'score': 0.849932074546814, 'coordinate': [685, 384, 756, 417], 'order': 11, 'polygon_points': [[685.0, 384.0], [756.0, 384.0], [756.0, 417.0], [685.0, 417.0]]}, {'cls_id': 22, 'label': 'text', 'score': 0.8802617192268372, 'coordinate': [545, 429, 884, 468], 'order': 12, 'polygon_points': [[545.0, 429.0], [884.0, 429.0], [884.0, 468.0], [545.0, 468.0]]}, {'cls_id': 22, 'label': 'text', 'score': 0.7239603400230408, 'coordinate': [618, 477, 817, 496], 'order': 13, 'polygon_points': [[618.0, 477.0], [816.0, 477.0], [816.0, 495.0], [618.0, 495.0]]}, {'cls_id': 22, 'label': 'text', 'score': 0.8236865997314453, 'coordinate': [543, 508, 666, 529], 'order': 14, 'polygon_points': [[542.9999389648438, 508.0], [664.9999389648438, 508.0], [664.9999389648438, 528.0], [542.9999389648438, 528.0]]}, {'cls_id': 16, 'label': 'number', 'score': 0.552054762840271, 'coordinate': [705, 555, 729, 571], 'order': 15, 'polygon_points': [[705.0, 555.0], [728.0, 555.0], [728.0, 570.0], [705.0, 570.0]]}, {'cls_id': 14, 'label': 'image', 'score': 0.8069510459899902, 'coordinate': [938, 0, 1099, 647], 'order': None, 'polygon_points': [[938.0, -2.0], [1099.0, -2.0], [1099.0, 647.0], [938.0, 647.0]]}]}}
Markdown document saved at markdown_0/doc.md
Output image saved at layout_det_res_0.jpg

PPIO 的算力市场模板致力于帮助企业及个人开发者降低大模型私有化部署的门槛,无需繁琐的环境配置,即可实现高效、安全的模型落地。

目前,PPIO算力市场已上线几十个私有化部署模板,除了 PaddleOCR-VL-1.5,你也可以将DeepSeek-OCR-2、AutoGLM-Phone-9B、 GLM-Image、PaddleOCR-VL 等模型快速进行私有化部署。

阅读更多

PPIO 零认证沙箱:Agent 安全的战场不只在模型侧,更在执行侧

PPIO 零认证沙箱:Agent 安全的战场不只在模型侧,更在执行侧

随着智能体大规模走进生产环节,AI 安全已从技术议题升级为企业级战略命题。 在上周五刚刚结束的腾讯全球数字生态大会上,PPIO 受邀参加 「Agent 安全专场」。PPIO Sandbox 产品专家宋书豪发表主题演讲《零认证沙箱 × 腾讯云安全 —— Agent 执行环境的信任边界重构》,系统阐述了 PPIO 在 Agent 执行安全领域的全新架构思路。 PPIO 沙箱是一款专为 Agent 场景设计的新一代运行时基础设施,提供了一个安全隔离的云端沙箱环境来执行 AI 生成的代码。PPIO 沙箱是国内首款兼容 E2B 的 Agent 沙箱,上线一年创建规模增长超 120 倍,每天运行沙箱数量上百万。 被忽视的场景:Agent 安全损失发生在沙箱,而非模型 模型决定 Agent 想做什么,但执行环境决定它能做成什么。 在这一背景下,宋书豪提出一个核心判断:“今天关于 Agent 安全的讨论,

By luigi
PPIO跻身中国MaaS市场头部阵营,位居独立服务商首位

PPIO跻身中国MaaS市场头部阵营,位居独立服务商首位

近日,国际数据公司(IDC)发布《中国AI软件市场半年度追踪,26H1》报告。报告显示,2026年上半年中国MaaS市场规模达到106.3亿元人民币,同比增长889.4%,正式迈入百亿级赛道。作为中国领先的独立 Agentic Cloud 服务商,PPIO 的MaaS 业务持续高速增长,与阿里巴巴、智谱、火山引擎、百度等企业的市场份额同处行业第一梯队,成为唯一上榜独立 MaaS厂商。 这一成绩既代表了市场对 PPIO的MaaS服务平台的广泛认可,也印证了在大厂林立,竞争激烈的MaaS市场中,PPIO 作为独立平台的价值, 既不自研大模型,也不绑定单一模型或算力厂商,从而能以涵盖百余款模型的开放生态,更加灵活和综合成本与体验更优的一站式模型服务,满足生产级的AI 落地需求。 IDC数据显示,2026上半年全市场Token消耗量达到2,857.9万亿,同比增长约432.5%。在这一轮市场爆发中,PPIO跑出了更快的增长速度。截至2026年9月,PPIO平台日均Token调用量达3.4万亿,同比增长近20倍,

By luigi
3.4万亿日均Token调用量,PPIO如何成为企业级Token调用的最佳实践?

3.4万亿日均Token调用量,PPIO如何成为企业级Token调用的最佳实践?

近日,由 DataFun 主办的 DACon 大会北京站圆满举办。PPIO 业务总监厉肃受邀出席,并在「企业模型组合:选型、路由、成本与治理」论坛发表主题演讲《PPIO 的Token 工厂与智能模型网关实践》。 一枚 Token 从任务请求发起,到任务执行结束会经历很多关键流程。PPIO 厉肃从客户使用 Token 的视角,分层拆解请求进入、路由判定、弹性调度、推理生产到任务编排各个环节,完整展示日均 Token 调用量 3.4 万亿背后, PPIO 如何把成本、延迟与智能逐一打磨到位。 1. 云的用户变了,Token 之痛随之而来 “云的第一用户,正在从「人」变成「Agent」。”PPIO 厉肃在分享中指出。 与传统云相比,

By luigi